Quantum Mechanics Demystified 2nd Edition David Mcmahon Apr 2026

A particle is in the state [ \psi(\theta,\phi) = \sqrt\frac158\pi \sin\theta \cos\theta e^i\phi. ] Find the expectation value ( \langle L_z \rangle ) in units of (\hbar).

[ \sigma_x |\psi\rangle = \beginpmatrix 0&1\1&0 \endpmatrix \frac1\sqrt2 \beginpmatrix 1\ i \endpmatrix = \frac1\sqrt2 \beginpmatrix i \ 1 \endpmatrix. ] [ \langle \psi | \sigma_x | \psi \rangle = \frac1\sqrt2 \beginpmatrix 1 & -i \endpmatrix \cdot \frac1\sqrt2 \beginpmatrix i \ 1 \endpmatrix = \frac12 (i - i) = 0. ] So (\langle S_x \rangle = 0). Quantum Mechanics Demystified 2nd Edition David McMahon

[ [\hatL_x, \hatL_y] = i\hbar \hatL_z, \quad [\hatL_y, \hatL_z] = i\hbar \hatL_x, \quad [\hatL_z, \hatL_x] = i\hbar \hatL_y. ] A particle is in the state [ \psi(\theta,\phi)

These operators satisfy the fundamental commutation relations: ] [ \langle \psi | \sigma_x | \psi

[ \hatL^2 |l,m\rangle = \hbar^2 l(l+1) |l,m\rangle, \quad l = 0, 1, 2, \dots ] [ \hatL_z |l,m\rangle = \hbar m |l,m\rangle, \quad m = -l, -l+1, \dots, l. ]

[ \hatS_z |+\rangle = \frac\hbar2 |+\rangle, \quad \hatS_z |-\rangle = -\frac\hbar2 |-\rangle. ] Define (\hatS_i = \frac\hbar2 \sigma_i), where (\sigma_i) are the Pauli matrices:

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