a(1)-5=-4→22=v j(10)-5=5=e l(12)-5=7=g y(25)-5=20=t → vegt
t=20 → s=19 k=11 → j=10 w=23 → v=22 n=14 → m=13 → sjvm tkwn-dmwak-mn-ajly
Try instead: (i.e., code was shifted -1 from plaintext). so decode with -5:
Better: ajly decode with shift -3: a(1)-3=-2→x(24) j(10)-3=7→g l(12)-3=9→i y(25)-3=22→v → xgiv — no. tkwn-dmwak-mn-ajly
Let’s decode with ROT11 (shift -15 or +11): t(20)-11=9=i k(11)-11=0→z(26) w(23)-11=12=l n(14)-11=3=c → izlc — not. Given the symmetry and common use in simple puzzles, the for tkwn-dmwak-mn-ajly using Caesar shift +5 (encode) , so decode with -5: