4.1 : A wave with a wavelength of 50 m is incident on a vertical wall. What is the reflection coefficient?
Solution: Using the run-up formula, we can calculate the run-up height: $R = \frac{H}{\tan{\beta}} = \frac{2}{0.1} = 20$ m.
5.1 : A wave with a wave height of 5 m and a wavelength of 100 m is approaching a beach with a slope of 1:20. What is the breaking wave height? Solution: Using the Sommerfeld-Malyuzhinets solution
1.1 : What is the difference between a water wave and a tsunami?
Solution: Using the Sommerfeld-Malyuzhinets solution, we can calculate the diffraction coefficient: $K_d = \frac{1}{\sqrt{2 \pi}} \int_{-\infty}^{\infty} e^{i k r \cos{\theta}} d \theta$. caused by wind friction
Solution: A water wave is a surface wave that travels through the ocean, caused by wind friction, while a tsunami is a series of ocean waves with extremely long wavelengths, caused by displacement of a large volume of water.
2.2 : What are the boundary conditions for a water wave problem? Solution: Using the Sommerfeld-Malyuzhinets solution
Solution: The reflection coefficient for a vertical wall is: $K_r = -1$.
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